Respuesta :

ANSWER

(1,0) is a solution

EXPLANATION

The given inequality is

[tex]y \leqslant |x + 2|- 3[/tex]

We substitute the point to see which ones satisfy the inequality.

For (1,0)

[tex]0\leqslant|1+ 2|- 3[/tex]

[tex]0\leqslant 0[/tex]

This is true.

(1,0) is a solution.

For (-1-1)

[tex]- 1\leqslant | - 1 + 2|-3[/tex]

[tex]- 1\leqslant-2[/tex]

False

(-1,-1) is not a solution.

For (0,0)

[tex]0\leqslant|0+2|-3[/tex]

[tex]0\leqslant- 1[/tex]

False.

For (0,1)

[tex]1\leqslant|0+ 2|-3[/tex]

[tex]1\leqslant-1[/tex]

This is also false