Question 14 Math Help please

ANSWER
(1,0) is a solution
EXPLANATION
The given inequality is
[tex]y \leqslant |x + 2|- 3[/tex]
We substitute the point to see which ones satisfy the inequality.
For (1,0)
[tex]0\leqslant|1+ 2|- 3[/tex]
[tex]0\leqslant 0[/tex]
This is true.
(1,0) is a solution.
For (-1-1)
[tex]- 1\leqslant | - 1 + 2|-3[/tex]
[tex]- 1\leqslant-2[/tex]
False
(-1,-1) is not a solution.
For (0,0)
[tex]0\leqslant|0+2|-3[/tex]
[tex]0\leqslant- 1[/tex]
False.
For (0,1)
[tex]1\leqslant|0+ 2|-3[/tex]
[tex]1\leqslant-1[/tex]
This is also false