if the diameter is 6 units, then the radius is half that, or 3.
[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} r=3 \end{cases}\implies A=\pi 3^2\implies A=9\pi \implies A\approx 28.27[/tex]
For this case we have that by definition, the area of a circle is given by:
[tex]A = \pi * r ^ 2[/tex]
Where:
r: It is the radius of the circle
If they tell us that the diameter is 6 inches, then the radius is 3 inches. replacing:
[tex]A = \pi * (3) ^ 2\\A = 9 \pi\\A = 28.26[/tex]
Thus, the area of the circle is 28.26 \ in ^ 2
ANswer:
[tex]28.26 \ in ^ 2[/tex]
