Respuesta :

luisejr77

Answer: 432 units²

Step-by-step explanation:

The figure is composed by two trapezoids.

The formula for calculate the area of a trapezoid is:

[tex]A=\frac{h}{2}(B+b)[/tex]

Where "B" is the larger base, "b" is the smaller base and "h" is the height.

Let be [tex]A_f[/tex] the area of the figure, [tex]A_1[/tex] the area of the trapezoid on the left and [tex]A_2[/tex] the area of the trapezoid of the right. Then the area of the figure will be:

 [tex]A_f=A_1+A_2[/tex]

[tex]A_f=\frac{h_1}{2}(B_1+b_1)+\frac{h_2}{2}(B_2+b_2)[/tex]

Substituting values, you get:

[tex]A_f=\frac{16units}{2}(25units+4units)+\frac{10units}{2}(25units+15units)=432units^2[/tex]

imlittlestar

Answer:

Area of given figure = 432 unit ²

Step-by-step explanation:

Points to remember

Area of trapezoid = h(a + b)/2

Where h - height  and a and b  are two parallel sides

To find the area of given figure

It is given two trapezoid

Area of 1st trapezoid

h = 16, a = 25 and b = 4

Area = h(a+ b)/2

 = 16(25 + 4)/2

 = 232 units ²

Area of 2nd trapezoid

h = 10, a = 25 and b = 15

Area = h(a+ b)/2

 = 10(25 + 15)/2

 = 200 units ²

Total area = 232 + 200 = 432 units²

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