Write a balanced equation for the combustion reaction that occurs between propane and oxygen.

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quasarJose quasarJose · Answer 1 · 2019-06-15T02:57:56+02:00

Answer:

Explanation:

The reaction between propane and oxygen is a combustion process for an hydrocarbon.

The formula of propane is given as C₃H₈ and oxygen is written as O₂

For this combustion reaction, the general equation is given as:

Cₓ[tex]H_{y}[/tex] + (x + [tex]\frac{y}{4}[/tex])O₂ → xCO₂ + [tex]\frac{y}{2}[/tex]H₂O

In the reaction between propane and oxygen,

x = 3

y = 8

The reaction is then written as:

C₃H₈ + (3 +[tex]\frac{8}{4}[/tex])O₂ → 3CO₂ + [tex]\frac{8}{2}[/tex]H₂O

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

09pqr4sT 09pqr4sT · Answer 2 · 2020-09-01T20:22:36+02:00

Answer:

[tex]\huge \boxed{\mathrm{C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O}}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Explanation:

[tex]\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O[/tex]

Balancing Carbon atoms on the right side,

[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O[/tex]

Balancing Hydrogen atoms on the right side,

[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]

Balancing Oxygen atoms on the left side,

[tex]\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]

[tex]\rule[225]{225}{2}[/tex]