find three consecutive even integers such that the sum of the least integer and the middle integer is 22 more than the greatest integer

Respuesta :

your integers are x, x+2, and x+4
x+x+2=22+x+4
2x+2=x+26
x=24
the integers are 24,26,28

The three consecutive even integers such that the sum of the least integer and the middle integer is 22 more than the greatest integer are 24, 26, and 28.

What are the consecutive numbers?

Numbers that follow each other continuously in the order from smallest to largest are called consecutive numbers.

Let the first consecutive number be x and the second consecutive number be (x+2).

And the third consecutive number be (x+4).

The sum of the least integer and the middle integer is 22 more than the greatest integer is given by;

x + x  + 2 = 22 + x + 4

2x + 2 = 26 + x

2x - x = 26 - 2

x = 24

The first consecutive number is = x = 24.

And the second consecutive number is = x + 2 = 24 + 2 = 26

And the third consecutive number is = x + 4 = 24 + 4 = 28

Hence, the three consecutive even integers such that the sum of the least integer and the middle integer is 22 more than the greatest integer are 24, 26, and 28.

Learn more about consecutive numbers here;

brainly.com/question/12556742

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