Answer:
D) 10^42
Explanation:
The electrostatic force between two electrons is given by
[tex]F_E = \frac{k q^2}{r^2}[/tex]
where
k is the Coulomb's constant
q is the electron charge
r is the separation between the electrons
The gravitational force between two electrons is
[tex]F_G = \frac{G m^2}{r^2}[/tex]
where
G is the gravitational constant
m is the electron mass
r is the separation between the electrons
So the ratio between the two forces is
[tex]\frac{F_E}{F_G}=\frac{k q^2}{G m^2}=\frac{(9\cdot 10^9 Nm^2 C^{-2} )(1.6 \cdot 10^{-19}C)^2}{(6.67\cdot 10^{-11}m^3 kg^{-1}s^{-2})(9.11\cdot 10^{-31} kg)^2}=4.2\cdot 10^{42}[/tex]