What is the slope of the line containing ( -3, 1 ) and (1 ,-2)

Answer:
D
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, 1) and (x₂, y₂ ) = (1, - 2)
m = [tex]\frac{-2-1}{1+3}[/tex] = [tex]\frac{-3}{4}[/tex] = - [tex]\frac{3}{4}[/tex]
The slope of the line containing points (-3, 1) and (1 ,-2) is Option (D) -3/4
The slope of a straight line gives the measure of its steepness and direction. It represents how steep a line can be.
The slope (m) of a straight line from two given points can be found by the formula,
Slope = m = (y2 - y1)/(x2 - x1)
where x1,x2 are the respective x-coordinates of the given points.
and y1,y2 are the respective y-coordinates of the given points .
By the problem, x1 = -3 , x2 = 1 , y1 = 1 , y2 = -2
Slope, m = (-2 -1)/(1 - (-3)) = -3/4
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