If f(x) = 1/9 x-2, what is f^-1 (x)?

Answer:
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
Given
y = [tex]\frac{1}{9}[/tex] x - 2
Multiply through by 9
9y = x - 18 ( add 18 to both sides )
x = 9y + 18
Change y back into terms of x, hence
[tex]f^{-1}[/tex] (x) = 9x + 18