Answer:
161.7 m/s
Explanation:
The kinetic energy of the car is given by
[tex]K=\frac{1}{2}mv^2[/tex]
where
m = 1650 kg is the mass of the car
v = 38.0 m/s is the speed
Substituting,
[tex]K=\frac{1}{2}(1650 kg)(38.0 m/s)^2=1.19\cdot 10^6 J[/tex]
The bycicle + rider has the same kinetic energy; moreover, their combined mass is
m = 91.0 kg
So, the speed of the bike should be
[tex]v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(1.19\cdot 10^6 J)}{91.0 kg}}=161.7 m/s[/tex]
Bicycle has a speed of 161.7 m/sec.
Given :
Mass of car = 1650 Kg
Speed = 38 m/sec
Mass of bicycle = 91 Kg
Bicycle and car travelling have same Kinetic Energy.
Solution :
Kinetic energy of the car is,
[tex]\rm KE = \dfrac{1}{2}mv^2[/tex]
[tex]\rm KE = \dfrac{1}{2}\times 1650 \times 38[/tex]
[tex]\rm KE_c_a_r = 1.19\times 10^6\; J[/tex]
Given that both have same kinetic energy. Therefore,
[tex]\rm KE_c_a_r = KE_b_i_c_y_c_l_e[/tex]
[tex]\rm 1.19\times10^6 = \dfrac{1}{2}\times91\times u^2[/tex]
[tex]\rm u = 161.7 \; m/sec[/tex]
Bicycle has a speed of 161.7 m/sec.
For more information, refer the link given below
https://brainly.com/question/15764612?referrer=searchResults
