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ANSWER

[tex]log_{s}(56)[/tex]

EXPLANATION

The given logarithmic expression is:

[tex] log_{s}(4 \times 7) + log_{s}(2) [/tex]

Recall and use the product rule of logarithm

[tex] log_{a}(b) + log_{a}(c) = log_{s}(bc) [/tex]

We apply this rule to obtain,

[tex]log_{s}(4 \times 7) + log_{s}(2) = log_{s}(4 \times 7 \times 2) [/tex]

We multiply out the argument to get;

[tex]log_{s}(4 \times 7) + log_{s}(2) = log_{s}(56) [/tex]

The correct answer is

[tex]log_{s}(56)[/tex]

Eduard22sly

When the expression Log₅ (4•7) + Log₅ 2 is express as a single logarithm, the result obtained is Log₅ 56

Data obtained from the question

  • Log₅ (4•7) + Log₅ 2
  • Single Log =?

How to express as single logarithm

Log₅ (4•7) + Log₅ 2

Log₅ (4 × 7) + Log₅ 2

Log₅ 28 + Log₅ 2

Recall

Log M + Log N = Log MN

Thus,

Log₅ 28 + Log₅ 2 = Log₅ (28 × 2)

Log₅ 28 + Log₅ 2 = Log₅ 56

Thus,

Log₅ (4•7) + Log₅ 2 = Log₅ 56

From the above illustration,

We can conclude that when Log₅ (4•7) + Log₅ 2 is written as a single log, the result is Log₅ 56

Learn more about Logarithm equation:

https://brainly.com/question/7302008

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