Answer:
A) 4/33 hour
Step-by-step explanation:
This is a distance = rate * time problem
We are given the distance and the rate, now we need to solve for the time:
[tex]\frac{4}{7}=4\frac{5}{7}t[/tex]
Let's change that mixed fraction into an improper one:
[tex]\frac{4}{7}=\frac{33}{7}t[/tex]
Now to solve for t we can multiply the 33/7 by its recirocal:
[tex](\frac{7}{33})\frac{4}{7}=\frac{33}{7}(\frac{7}{33})t[/tex]
Multiplying a fraction by its reciprocal = 1, so that leaves only a t on the right:
[tex](\frac{7}{33})\frac{4}{7}=t[/tex]
The 7's cancel out on the left and that leaves you with
[tex]t=\frac{4}{33}hr[/tex]
