What is the greatest common factor of 8m, 36m3, and 12

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kudzordzifrancis kudzordzifrancis · Answer 1 · 2019-06-06T21:10:40+02:00

ANSWER

GCF=4

EXPLANATION

The given monomials are:

[tex]8m = {2}^{3} m[/tex]

[tex]36 {m}^{3} = {2}^{2} \times {3}^{2} {m}^{3} [/tex]

[tex]12 = {2}^{2} \times 3[/tex]

The greatest common factor is the product of all the least powers of the common factors.

We can see that:

[tex] {2}^{2} [/tex]

is the common to all the factors.

Therefore the greatest common factor is

[tex] {2}^{2} = 4[/tex]

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luisejr77 luisejr77 · Answer 2 · 2019-06-06T21:14:47+02:00

Answer: [tex]GCF=4[/tex]

Step-by-step explanation:

To find the Greatest Common Factor (GCF) of 8m, 36m³, and 12, you need to descompose them into their prime factors. Then:

[tex]8m=2*2*2*m=2^3*m\\\\36m^3=2*2*3*3*m^3=2^2*3^2*m^3\\\\12=2*2*3=2^2*3[/tex]

You can observe that the common factor with the lowest exponent is the following:

[tex]2^2[/tex]

Therefore, the Greatest Common Factor (GCF) of 8m, 36m³, and 12 is:

[tex]GCF=2^2\\GCF=4[/tex]