The kinetic energy of the automobile weighing 4345lb and with a speed of 75mph is 1.1077 × 10⁶J
Given the data in the question;
- Mass of the automobile [tex]m = 4345lb = 1970.859 kg[/tex]
[we convert from pound to kilogram]
- Velocity of the automobile; [tex]v = 75mph = 33.528m/s[/tex]
[ we convert from miles per hour to meter per second]
Kinetic energy; [tex]K.E = ?[/tex]
We know that, Kinetic Energy ( K.E ) is a form of energy that a matter possesses by reason of its motion.
It is directly proportional to the mass of the matter and to the square of its velocity.
That is; [tex]K.E = \frac{1}{2} mv^2[/tex]
To find the Kinetic Energy, we simply substitute our given values into the equation
[tex]K.E = \frac{1}{2}\ * 1970.859kg\ *\ ( 33.528m/s)^2\\\\K.E = 1107747.69 kg.m^2/s^2\\\\K.E = 1.1077 * 10^6 J[/tex]
Therefore, the kinetic energy of the automobile weighing 4345lb and with a speed of 75 mph is 1.1077 × 10⁶J
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