let's notice that this triangular pyramid has a triangular base, that triangle has a base of 14 and an altitude of 8.485, whilst the pyramid also has a height of 12.
[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=&area~of\\ &its~base\\ h=&height\\ \cline{1-2} h=&12\\ B=&\frac{1}{2}(14)(8.485) \end{cases}\implies V=\cfrac{1}{3}\left[ \cfrac{1}{2}(14)(8.485) \right](12) \\\\\\ V=4\cdot (7\cdot 8.485)\implies V=237.58[/tex]
