Answer:
first option
(8, -1)
Step-by-step explanation:
We have the following system of linear equations
[tex]\left \{{{x+6y=2} \atop {5x+4y=36}} \right.[/tex]
To solve the system multiply the first equation by -5 and then add it to the second equation.
[tex]-5*(x+6y)=2*(-5)[/tex]
[tex]-5x -30y=-10\\5x+4y=36[/tex]
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[tex]-26y = 26[/tex]
[tex]y = -1[/tex]
substitute [tex]y = -1[/tex] in any of the two equations and then solve for x
[tex]5x+4(-1)=36\\5x-4=36\\5x = 36+4\\5x = 40\\[/tex]
[tex]x =8[/tex]
The answer is the first option
(8, -1)
