Respuesta :

imlittlestar

Answer:

The correct answer is first option

(2, 3)

Step-by-step explanation:

It is given that,

3y = -x + 11  and

x + 4y = 14

To find the solutions

The given equation can be written as,

x + 3y = 11 --------(1)

x + 4y = 14  -------(2)

Subtract (1)  from (2) we get

y = 3

Substitute vale of y in eq(1)

x + 3*3 = 11

x = 11 - 9 = 2

Therefore x = 2 and y = 3

The correct answer is first option

luisejr77

Answer:

first option

(2, 3)

Step-by-step explanation:

We have the following system of linear equations

[tex]\left \{{{3y=-x+11} \atop {x+4y=14}} \right.[/tex]

This is the same as

[tex]\left \{{{x + 3y=11} \atop {x+4y=14}} \right.[/tex]

To solve the system multiply the first equation by -1 and then add it to the second equation.

[tex]-1*(x+3y)=11*(-1)[/tex]

[tex]-x -3y=-11\\x+4y=14[/tex]

-----------------

[tex]y = 14-11[/tex]

[tex]y = 3[/tex]

substitute [tex]y = 3[/tex] in any of the two equations and then solve for x

[tex]x+4(3)=14\\x+12=14\\x =14-12\\x = 2\\[/tex]

[tex]x =2[/tex]

The answer is the first option

(2, 3)