Answer: The equation of the circle whose center is at (2, 1) and radius is 3 is [tex](x-2)^2+(y-1)^2=9[/tex]
Step-by-step explanation:
We know that the equation of a circle having center at (h,k) and radius r is given by :-
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Given : The center of the circle : (2, 1)
The radius of the circle : 3 units
Then the equation of a circle with center at (2, 1) and radius is 3 is will be :-
[tex](x-2)^2+(y-1)^2=3^2\\\\\Rightarrow\ (x-2)^2+(y-1)^2=9[/tex]
