Answer:
The correct answer option is B. 60%.
Step-by-step explanation:
We are given the results of a survey which asked the students whether they have any siblings and pets.
We are to determine the likelihood that student has a pet, given that he or she does not have a sibling.
Assuming A to be the event showing that a student does not have a sibling and B to be the event that a students has a pet.
Then P(B|A) is:
[tex]P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}[/tex]
Substituting the given values, P(A)=0.25 and P(A∩B)=0.15:
[tex]P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6[/tex]
So the percentage will be:
[tex]0.6\times 100 = [/tex] 60%
