Which expression is equivalent to 2x2 - 2x + 7?
- (4x+12) + (2x2–6x+5)
• (x2–5x+13)+(x2 +3X-6)
. (4x? -6x+ 11 ) + (2x² - 4x+4)
(5x® – 8x+120) + (-3x2 + 10x= 13)​

Respuesta :

It basically (B) since it’s substituting x=0
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Answer:

B) [tex](x^2 - 5x + 13) +(x^2 + 3x - 6)\\[/tex]

Step-by-step explanation:

Let's simplify the given options and find the correct answer.

The given expression is [tex]2x^2 - 2x + 7[/tex]

Let's take the option A and simplify.

[tex]-(4x + 12) + (2x^2 - 6x + 5)[/tex]

Distributing the negative sign and simplify.

[tex]-4x - 12 + 2x^2 -6x + 5[/tex]

Simplify the like terms.

[tex]2x^2 -10x - 7[/tex]

Which is not equal to the given expression.

Let's take the option B and simplify.

[tex](x^2 - 5x + 13) +(x^2 + 3x - 6)\\[/tex]

Simplify the like terms, we get

[tex]x^2 + x^2 -5x +3x +13 -6[/tex]

[tex]2x^2 -2x +7[/tex]

Which is equal to the given expression [tex]2x^2 -2x +7[/tex]

Therefore, the answer is B) [tex](x^2 - 5x + 13) +(x^2 + 3x - 6)\\[/tex]