Answer: Option b
[tex]f (1) = 0[/tex]
Step-by-step explanation:
For a function of the form
[tex]f (x) = ax ^ n + bx ^ {n-1} + ... + c[/tex]
Where n is the main exponent of the polynomial and a, b c are the coefficients of the variables then this polynomial can be written based on its factors as
[tex]f (x) = a (x-h) (x-k) (x-s)...[/tex]
Where [tex]x = h[/tex], [tex]x = k[/tex], [tex]x = s[/tex], ... are the points where [tex]f(x) = 0[/tex]
Therefore if for this case we know that
[tex](x-1)[/tex] is a factor of a polynomial function [tex]f (x)[/tex] then it is fulfilled that
[tex]f (1) = 0[/tex]
