contestada

this table shows the number of points two teams scored in five games


team 1 team 2
51 27
47 55
35 53
48 38
64 41

what is the difference in the mean absolute deviation of the two teams

Respuesta :

lucic

Answer:

2.16

Step-by-step explanation:

The question is on mean absolute deviation

The general formula ,

Mean deviation = sum║x-μ║/N where  x is the each individual value, μ is the mean and N is number of values

Team 1

Finding the mean ;

[tex]mean= \frac{51+47+35+48+64}{5}  =49[/tex]

Points     Absolute Deviation from mean

51                          2

47                         2

35                        14

48                         1

64                         15

Sum                    34          

Absolute mean deviation = 34/5= 6.8

Team 2

Finding the mean

[tex]mean=\frac{27+55+53+38+41}{5} = 42.8[/tex]

Points                      Absolute deviation from the mean

27                                    15.8

55                                    12.2

53                                     10.2

38                                      4.8

41                                       1.8

Sum                                 44.8        

Absolute deviation from the mean = 44.8/5 =8.96

Solution

Difference in mean absolute deviation of the two teams = 8.96-6.8 = 2.16

Otras preguntas