Answer:
2.45 N/m
Explanation:
We can find the spring constant by using Hooke's law:
[tex]F=kx[/tex]
where
F is the force applied to the spring
k is the spring constant
x is the stretching of the spring
Here, the force applied is the weight of the mass hanged on the spring. The mass is
m = 10 g = 0.010 kg
So the weight is
[tex]F=mg=(0.010 kg)(9.8 m/s^2)=0.098 N[/tex]
while the stretching is
x = 4 cm = 0.04 m
So the spring constant is
[tex]k=\frac{F}{x}=\frac{0.098 N}{0.04 m}=2.45 N/m[/tex]
