pair with their perpendicular equations are
y = - (6/5)x + 1
y = (6/5)x - 5
y = (4/7)x + 9
y = - (4/7)x + 2
What is condition of perpendicular line?
The given line is perpendicular to the required line under the condition of perpendicular lines m1×m2=–1.
As, m1*m2=-1
m1= -1/m2
For first equation
y = (5/6)x - 7
m1= 5/6
So, m2= -1/m2= -6/5
Hence, the equation of perpendicular line is y = - (6/5)x + 1.
Similarly,
y = (5/6)x - 7
m1= 5/6
So, m2= -1/m2= -6/5
Hence, the equation of perpendicular line is y = (6/5)x - 5.
again,
y = - (7/4)x - 1
m1=-7/4
So, m2= -1/m2= 7/4
Hence, the equation of perpendicular line is y = (4/7)x + 9
again,
y = (7/4)x - 2
m1= 7/4
So, m2= -1/m2= -4/7
Hence, the equation of perpendicular line is y = - (4/7)x + 2.
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