Answer:
The solution is:
[tex](0, 1)[/tex]
Step-by-step explanation:
We have the following equations
[tex]9x + 4y = 4[/tex]
[tex]-5x + 7y = 7[/tex]
To solve the system multiply by [tex]\frac{9}{5}[/tex] the second equation and add it to the first equation
[tex]-5*\frac{9}{5}x + 7\frac{9}{5}y = 7\frac{9}{5}[/tex]
[tex]-9x + \frac{63}{5}y = \frac{63}{5}[/tex]
[tex]9x + 4y = 4[/tex]
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[tex]\frac{83}{5}y=\frac{83}{5}[/tex]
[tex]y=1[/tex]
Now substitute the value of y in any of the two equations and solve for x
[tex]9x + 4(1) = 4[/tex]
[tex]9x +4 = 4[/tex]
[tex]9x = 4-4[/tex]
[tex]9x = 0[/tex]
[tex]x=0[/tex]
The solution is:
[tex](0, 1)[/tex]
