Answer:
55 inches
Step-by-step explanation:
This question is on z-score for a sample
The general formula for finding z score for a sample is;
z=(x-μ)/δ...................where x is the sample is the height , μ is the mean and δ is the standard deviation
Given;
z=3 x=? μ=49 δ=2
Substitute values above in the general formulae
z=(x-μ)/δ
3=(x-49)/2
[tex]3=\frac{x-49}{2} \\\\\\3*2=x-49\\\\\\6=x-49\\\\\\6+49=x\\\\\\55=x[/tex]
Answer:
Step-by-step explanation:
To solve this problem we need to use the following formula
[tex]Z=\frac{x- \mu}{\sigma}[/tex]
Where [tex]Z[/tex] is the z-value, [tex]\mu[/tex] is the mean, [tex]\sigma[/tex] is the standard deviation and [tex]x[/tex] is the height of the student.
In this case, we have
[tex]Z=3\\\mu=49\\\sigma=2[/tex]
Replacing all these values, we have
[tex]3=\frac{x- 49}{2}\\6=x-49\\x=6+49\\x=55[/tex]
Therefore, the student is 55 inches tall.
