Answer:
Step-by-step explanation:
The first one I would factor the difference of cubes on top and then cancel a common factor this would end up giving you sin^2(A/2)+sin(A/2)cos(A/2)+cos^2(A/2)
(the 1st+3rd term here actually equals 1)
now you have
1+sin(A/2)cos(A/2)
1+1/2*2sin(A/2)cos(A/2) (this step was just to help show how I'm going to use the next identity)
1+1/2sin(A) (double angle identity for sine)
hint for the next one: I would multiply top and bottom by bottom's conjugate first
