Answer:
The length is [tex]18\ m[/tex] and the width is [tex]10\ m[/tex]
Step-by-step explanation:
Let
x -----> the length of the rectangle
y -----> the width of the rectangle
we know that
The perimeter of rectangle is equal to
[tex]P=2(x+y)[/tex]
[tex]P=56\ m[/tex]
so
[tex]56=2(x+y)[/tex]
[tex]28=(x+y)[/tex] ------> equation A
[tex]x=y+8[/tex] -----> equation B
Substitute equation B in equation A and solve for y
[tex]28=(y+8+y)[/tex]
[tex]28=2y+8[/tex]
[tex]2y=20[/tex]
[tex]y=10\ m[/tex]
Find the value of x
[tex]x=10+8=18\ m[/tex]
therefore
The length is [tex]18\ m[/tex] and the width is [tex]10\ m[/tex]
