Respuesta :

Call O the mass of oxygen and C the mass of carbon in the sample. Now use two equations, two unknowns to solve.

From the first sentence we know that:
O = 1.33C

From be second sentence we know that:
C + O = 16.03

Sub the first into the second:
C + 1.33C = 16.03
2.33C = 16.03
C = 6.88

The mass of carbon in the sample is 6.88g.

There are 6.88 g of carbon in 16.03 g sample of carbon monoxide.

Carbon monoxide has formula as CO.

C => carbon

O => oxygen

From the question given above, we were told that there is always 1.33 g of oxygen for every 1 g of carbon. Thus,

O = 1.33C ............. (1)

We were also told that the mass of CO is 16.03 g i.e

C + O = 16.03 ........... (2)

Summary:

O = 1.33C ............. (1)

C + O = 16.03 ........... (2)

From the equation above, we can obtained the mass of Carbon (C) as follow:

C + O = 16.03

O = 1.33C

C + 1.33C = 16.03

2.33C = 16.03

Divide both side by 2.33

C = 16.03 / 2.33

C = 6.88 g

Therefore, 16.03 g of the sample of carbon monoxide contains 6.88 g of carbon.

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