Respuesta :
[tex]\bf f(x)=\stackrel{\stackrel{m}{\downarrow }}{4} x+10\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \begin{array}{ccll} x&g(x)\\ \cline{1-2} 2&5\\4&7\\6&9 \end{array}~\hfill \begin{array}{llll} (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{9}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-5}{6-2}\implies \cfrac{4}{4}\implies \stackrel{\stackrel{m}{\downarrow }}{1} \end{array}[/tex]
well, clearly 4 > 1.
Answer:
f(x) has a greater slope.
Step-by-step explanation:
The slope of a function in the form of y=Mx+C is represented by the letter M, so the slope in the function F(x) =4.
Now when you have a function but you only have a table to evaluate it, to calculate the slope you have the next formula:
[tex]m=\frac{y^{2}- y^{1}}{x^{2} -x^{1} }[/tex]
You just have to pick two points from the table to use in the formula, we´ll use (4,7) as our point 1 and
(6,9) as our point 2.
This means that:
[tex]x^{1}=4[/tex] [tex]y^{1}=7[/tex]
[tex]x^{2}=6[/tex] [tex]y^{2}=9[/tex]
Now you just put it into the formula:
[tex]m=\frac{9-7}{6-4}[/tex]
[tex]m=\frac{2}{2}[/tex]
[tex]m=1[/tex]
Now that you have both slopes, you can see that the slope of g(x)=1 and the slope of f(x)=4, and you can see that f(x) has a greater slope thatn g(x).