Answer:
[tex]\large\boxed{a.\ -30}[/tex]
Step-by-step explanation:
[tex]\dfrac{y}{3}+8=-2\qquad\text{subtract 8 from both sides}\\\\\dfrac{y}{3}+8-8=-2-8\\\\\dfrac{y}{3}=-10\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{y}{3\!\!\!\!\diagup_1}=(3)(-10)\\\\y=-30[/tex]
