Answer:
T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.
Explanation:
Rate of the reaction = - d[reactants]/dt = d[products]/dt
∵ Rate at T1 (1.8 x 10⁻⁶ M/s) > rate at T2 (1.0 x 10⁻⁶).
∴ T1 < T2, which means that T1 is shorter than T2.
As, the rate increases, the remaining of the reactants decrease and products formed increase.
So, concentration of reactants at the end of T1 is lower than that of T2 and the concentration of products at the end T1 is higher than that of T2.
T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.