Answer:
1[tex]\frac{1}{2}[/tex] + [tex]1\frac{1}{3}[/tex]p - 8
Step-by-step explanation:
The sum of one-half of d and one-third of p, minus 8;
i.e
1[tex]\frac{1}{2}[/tex] + [tex]1\frac{1}{3}[/tex]p - 8
Putting it into improper fraction becomes:
[tex]\frac{3}{2}[/tex]d + [tex]\frac{4}{3}[/tex]p - 8
