[tex]
2x^2+5x+8=0 \\
x=\dfrac{-5+\vee-\sqrt{5^2-2\cdot2\cdot8}}{2\cdot2} \\
x=\dfrac{-5+\vee-\sqrt{25-64}}{4} \\
x=\dfrac{-5+\vee-\sqrt{-39}}{4}\Longrightarrow x\notin\mathbb{R} \\
x\notin\mathbb{R}\Longrightarrow x\in\mathbb{C}
[/tex]
So no real solutions for x. But two complex solutions for x.
[tex]
x_1=\boxed{\dfrac{-5-39i}{4}} \\ \\
x_2=\boxed{\dfrac{-5+39i}{4}}
[/tex]
Hope this helps.
r3t40
