The equation of the given circle is Option(A) [tex](x-2)^{2} + (y - 1)^{2} = 1[/tex] .
What is equation of circle ?
The standard equation of any circle is given as -
[tex](x-h)^{2} + (y - k)^{2} = r^{2}[/tex]
where (h,k) is the coordinate of the center of the given circle and r is the length of radius of the circle.
How to form the equation of the given circle ?
In the diagram given aside, we can see that the circle has its center at (2,1) and also the radius of the circle measures 1 units.
Thus, we have h = 2 , k = 1 and r = 1 in the standard representation.
The equation of the circle is -
⇒ [tex](x-2)^{2} + (y - 1)^{2} = 1^{2}[/tex]
∴ [tex](x-2)^{2} + (y - 1)^{2} = 1[/tex]
Therefore, the equation of the given circle is Option (A) [tex](x-2)^{2} + (y - 1)^{2} = 1[/tex] .
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