Answer:
89.0 g.
Explanation:
- The balanced chemical equation between CuO and HCl is:
2Na + Cl₂ → 2NaCl,
It is clear that 2 mol of Na react with 1 mol of Cl₂ to produce 2 mol of NaCl.
- Firstly, we need to calculate the no. of moles of (35.0 g of Na) and (100.0 g Cl₂):
no. of moles of Na = mass/molar mass = (35.0 g)/(22.989 g/mol) = 1.522 mol.
no. of moles of Cl₂ = mass/molar mass = (100.0 g)/(70.906 g/mol) = 1.41 mol.
From the balanced equation: Na reacts with Cl₂ with (2: 1) molar ratio.
∴ 1.522 mol of Na "limiting reactant" reacts completely with 0.761 mol of Cl₂ "excess reactant".
- To calculate the mass of the produced salt (CuCl₂):
2 mol of Na produces → 2 mol of NaCl, from stichiometry.
∴ 1.522 mol of Na produces → 1.522 mol of NaCl.
∴ The mass of the produced salt (NaCl) = (no. of moles)(molar mass) = (1.522 mol)(58.44 g/mol) = 88.95 g ≅ 89.0 g.
