contestada

What are the solutions for x when y is equal to 0 in the following quadratic
function?

y = x ^+ 6x +12

OA) X = 3 or x = 4
OB) x= -3 or x = 4
OC) x= 3 or x = 4
OD) x= -3 or x = 4
O E) no solution​

Respuesta :

alinakincsem

Answer:

The correct answer option is E) No solution.

Step-by-step explanation:

We are given the following quadratic equation which we are to solve for x when the value of y is 0:

[tex]y = x ^2+ 6x +12[/tex]

[tex]x ^2+ 6x +12=0[/tex]

Using the quadratic formula since there are no factors:

[tex]x=\frac{-b \pm \sqrt{b^2-4ac }}{2a}[/tex]

Substituting the values in the formula to get:

[tex]x=\frac{-6 \pm \sqrt{6^2-4(1)(12) }}{2(1)}[/tex]

[tex]x=-3+\sqrt{3}i[/tex] or [tex]x=-3-\sqrt{3}i[/tex]

There are no real number solutions to this quadratic equation.

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