The measure of one of the small angles of a right triangle is 18 less than twice the measure of the other small angle. Find the measure of both angles. Use integers only

Respuesta :

Answer:

36° and 54°

Step-by-step explanation:

We are given that one of the small angles of a right angled triangle is 18 less than twice the measure of the other small angle.

We are to find the measure of both angles.

Assuming [tex]x[/tex] to be the other small angle, 8 less than twice the measure of the other small angle = [tex]2x-18[/tex].

Summing all three angles up ti get:

[tex]x+(2x-18)+90=180[/tex]

[tex]3x=180-90+18[/tex]

[tex]3x=108[/tex]

[tex]x=\frac{108}{3}[/tex]

x = 36°

So other angle will be [tex]2(36)-18=[/tex] 54°.

Answer:

36° and 54°

Step-by-step explanation:

let x be one of the smaller angles, then the other smaller angle is 2x - 18 ( 18 less than twice the other )

Since it is a right triangle then the sum of the 2 smaller angles equals 90, so

x + 2x - 18 = 90

3x - 18 = 90 ( add 18 to both sides )

3x = 108 ( divide both sides by 3 )

x = 36

One angle = 36°

the other angle = (2 × 36) - 18 = 72 = 18 = 54°