contestada

An object was measured by a worker as
17.4cm long, however, the manufacturer
specifications list the length of the object at
17.9cm. What is the percent error in the
workers measurement?

Respuesta :

znk

Answer:

[tex]\boxed{2.8 \, \%}[/tex]

Explanation:

[tex]\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%[/tex]

Data:

Predicted = 17.4 cm

     Actual = 17.9 cm

Calculation:

[tex]\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}[/tex]