contestada

At a game show, there are 8 people (including you and your friend) in the
front row.
The host randomly chooses 3 people from the front row to be contestants.
The order in which they are chosen does not matter.
How many ways can you and your friend both be chosen?

At a game show there are 8 people including you and your friend in the front row The host randomly chooses 3 people from the front row to be contestants The ord class=

Respuesta :

mariahderenzo

Answer:

6

Step-by-step explanation:

For both to be chosen the other spot can be taken by any of the other 6 people in the row. So six possibilities

Answer:

A. [tex]^6C_1=6[/tex]

Step-by-step explanation:

Given,

The total number of people = 8,

The number of people have to chosen = 3,

Since, me and my friend both have to be chosen,

So, the remaining number of people = 8 - 2 = 6,

And, the number of remaining number of people have to be chosen = 3 - 2 = 1

Also, the order does not matter,

Hence, the total way of choosing = Total combination of me and my friend × total combination of choosing 1 person out of 6 people

[tex]=^2C_2\times ^6C_1[/tex]

[tex]=1\times ^6C_1[/tex]

[tex]=6[/tex]

Option A is correct.

Otras preguntas