Answer:
[tex]\boxed{\text {1.93 mol}}[/tex]
Explanation:
1. Calculate the moles of N₂H₄
1 mol of N₂H₄ = 32.05 g
[tex]\text{Moles of N$_{2}$H$_{4}$} = \text{31 g N$_{2}$H$_{4}$} \times \dfrac{\text{1 mol N$_{2}$H$_{4}$}}{\text{32.05 g N$_{2}$H$_{4}$}} = \text{0.967 mol N$_{2}$H$_{4}$}[/tex]
2. Calculate the moles of N
[tex]\text{Moles of N} = \text{0.967 mol N$_{2}$H$_{4}$}\times \dfrac{\text{2 mol N}}{\text{1 mol N$_{2}$H$_{4}$}} = \textbf{1.93 mol N$_{2}$H$_{4}$}\\\\\text{There are }\boxed{\textbf{1.93 mol of N}} \text{ in 31 g of N$_{2}$H$_{4}$}[/tex]
