Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:

f(x) = 2x − 20

g(x) = x − 1

−5
5
one sixth
30

Respuesta :

Answer: Choice A)  -5

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Plug x = -5 into f(x)

f(x) = 2x-20

f(-5) = 2(-5) - 20

f(-5) = -10-20

f(-5) = -30

Then plug x = -5 into g(x)

g(x) = x-1

g(-5) = -5-1

g(-5) = -6

Divide the two results

(f/g)(-5) = f(-5)/g(-5)

(f/g)(-5) = (-30)/(-6)

(f/g)(-5) = -5

For this case we have the following functions:

[tex]f (x) = 2x-20\\g (x) = x-1[/tex]

We must find [tex]\frac {f (-5)} {g (-5)}[/tex], then:

We have in mind that:

[tex]+ * - = -[/tex]

Equal signs are added and the same sign is placed.

[tex]\frac {f (-5)} {g (-5)} = \frac {2 (-5) -20} {- 5-1} = \frac {-10-20} {- 6} = \frac {-30} {- 6} = 5[/tex]

Answer:

5