Respuesta :
Answer:
{-6,4}
Step-by-step explanation:
Given
x-4y=-22 Eqn 1
x-y=-10 Eqn 2
Subtracting both equations:
The left hand side of equation 2 will be subtracted from left hand side of eqn 1 and the right side of equation 2 will be subtracted from right hand side of eqn 1.
[tex](x-4y)-(x-y)=-22-(-10)\\x-4y-x+y=-22+10\\-4y+y=-12\\-3y=-12\\\frac{-3y}{-3}=\frac{-12}{-3}\\ y=4[/tex]
Putting y=4 in eqn 2
[tex]x-4=-10\\x=-10+4\\x=-6\\So,\\Solution Set = \{-6,4\}[/tex]
Answer:
{x, y} = {-6, 4}
Step-by-step explanation:
It is given that,
x - 4y = -22 ------(1)
x - y= -10 -------(2)
To ind the value of x and y
subtract eq(2) from eq(1)
x - 4y = -22 ------(1)
x - y= -10 -------(2)
0 -3y = -12
3y = 12
y = 12/3 = 4
Substitute the value of y in eq (1)
x - 4y = -22 ------(1)
x - (4*4) = -22
x - 16 = -22
x = -22 +16 = -6
Therefore {x, y} = {-6, 4}