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A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.

The velocity of the projectile the moment it was launched, rounded to the nearest hundredth, is

Respuesta :

MathPhys

Answer:

5.09 m/s

Explanation:

Use the height to find the time it takes to land:

y = y₀ + v₀ᵧ t + ½ gt²

0 = 8.0 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.28 s

Now use the horizontal distance to find the initial velocity.

x = x₀ + v₀ₓ t + ½ at²

6.5 m = 0 m + v₀ (1.28 s) + ½ (0 m/s²) (1.28 s)²

v₀ = 5.09 m/s

aaliyahanniebiella

Answer:

5.09 m/s

Explanation:

Edge2021 Physics

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