Respuesta :
X= -b +- square root of b^2-4ac
——————-
2a
6 +- square root of 36-4(2)(1)
———
4
6+- square root of 32
———
4
6+- 4 square root of 2
———
4
3 +- 2 square root of 2
———
2
——————-
2a
6 +- square root of 36-4(2)(1)
———
4
6+- square root of 32
———
4
6+- 4 square root of 2
———
4
3 +- 2 square root of 2
———
2
Answer with Step-by-step explanation:
We have to solve the equation 2x²-6x+1=0
the solution of the equation ax²+bx+c=0 is given by
[tex]x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\ and\ x=\dfrac{-b-\sqrt{b^2-4ac}}{2a}[/tex]
Here a=2,b=-6 and c=1
[tex]x=\dfrac{6+\sqrt{6^2-4\times 2\times 1}}{2}\ and\ x=\dfrac{6-\sqrt{6^2-4\times 2\times 1}}{2}\\\\x=\dfrac{6+\sqrt{36-8}}{2}\ and\ x=\dfrac{6-\sqrt{36-8}}{2}\\\\x=\dfrac{6+\sqrt{28}}{2}\ and\ x=\dfrac{6-\sqrt{28}}{2}\\\\x=\dfrac{6+2\sqrt{7}}{2}\ and\ x=\dfrac{6-2\sqrt{7}}{2}\\\\x=3+\sqrt{7}\ and\ x=3-\sqrt{7}[/tex]
Hence, solution of 2x²-6x+1=0 is:
[tex]x=3+\sqrt{7}\ and\ x=3-\sqrt{7}[/tex]