Answer:
[tex]V=312\pi\ mm^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the composite figure is equal to the volume of a semi-sphere plus the volume of the cone
so
[tex]V=\frac{4}{6}\pi r^{3} +\frac{1}{3} \pi r^{2} h[/tex]
we have
[tex]r=6\ mm[/tex]
[tex]h=14\ mm[/tex]
substitute
[tex]V=\frac{4}{6}\pi (6)^{3} +\frac{1}{3} \pi (6)^{2} (14)[/tex]
[tex]V=144\pi +168\pi[/tex]
[tex]V=312\pi\ mm^{3}[/tex]
