For this case we have by definition, that the electrical power is given by:
[tex]P = I ^ 2 * R[/tex]
Where:
P: It's the power
I: It's the current
R: It's the resistance
Clearing the current:
[tex]I ^ 2 = \frac {P} {R}\\I = \pm \sqrt {\frac {P} {R}}[/tex]
We choose the positive value:
[tex]I = \sqrt {\frac {500} {25}}\\I = \sqrt {20}\\I = 4.47A[/tex]
ANswer:
Option A
