Answer:
5/12 ≈ 0.41667
Step-by-step explanation:
If the first die rolls a 1 and the second die rolls a 1, then the sum is 2.
If the first die rolls a 1 and the second die rolls a 2, then the sum is 3.
Repeating this, we can build a table showing all the possible outcomes:
[tex]\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right][/tex]
As we can see, of the 36 possible outcomes, 15 are greater than seven. So the probability is 15/36, which reduces to 5/12.
