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A uniform conducting rod of length 22 cm has a potential difference across its ends equal to 41 mV (millivolts). What is the magnitude of the electric field inside the conductor in units of N/C?

Respuesta :

skyluke89

Answer:

0.186 N/C

Explanation:

The relationship between electric field strength and potential difference is:

[tex]E=\frac{\Delta V}{d}[/tex]

where

E is the electric field strength

[tex]\Delta V[/tex] is the potential difference

d is the distance

Here we have

[tex]\Delta V=41 mV=0.041 V[/tex]

d = 22 cm = 0.22 m

So the electric field magnitude is

[tex]E=\frac{0.041 V}{0.22 m}=0.186 N/C[/tex]

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