Answer:
5 units at 203 degrees
Explanation:
The equilibrant vector must have components that are opposite to those of the initial vector.
The components of the initial vector are:
[tex]v_x = v cos \theta = 5 cos 23^{\circ}=4.60\\v_y = v sin \theta = 5 sin 23^{\circ} = 1.95[/tex]
So the components of the equilibrant vector must be
[tex]v_x = -4.60\\v_y = -1.95[/tex]
which means its magnitude is
[tex]v=\sqrt{v_x^2 + v_y^2}= 5[/tex] (same magnitude as the initial vector)
and it is located in the 3rd quadrant, so its angle will be
[tex]\theta = 180^{\circ} + tan^{-1} (\frac{1.95}{4.60})=203^{\circ}[/tex]
