Adimas found the mean of her 11 math test scores for the first semester.

x = ≈ 81
Using 81 as the mean, find the variance of her grades rounded to the nearest hundredth.

σ2 =

Find the standard deviation of her grades rounded to the nearest hundredth.

σ =

Respuesta :

Answer: O^2= 71.36

               O=8.45  

Answer:

The complete question is attached.

To find the variance and deviation, we have to use their definition or formulas:

Standard deviation.

[tex]\sigma=\sqrt{\frac{\sum (x- \mu)^{2} }{N}}[/tex]

So, first we have to find the difference between each number and the mean:

76-81=-5

87-81=6

65-81=-16

88-81=7

67-81=-14

84-81=3

77-81=-4

82-81=1

91-81=10

85-81=4

90-81=9

Now, we have to elevate each difference to the squared power and then sum all:

[tex]25+36+256+49+196+9+16+1+100+16+81=785[/tex]

Then, we replace in the formula:

[tex]\sigma=\sqrt{\frac{785}{11}} \approx 8.45[/tex]

Variance.

The variance is just the squared power of the standard deviation. So:

[tex]\sigma^{2}=(8.45)^{2}=71.40[/tex]

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